Solved The Curve Y Ax 2 Bx C Passes Through The Point Chegg Com
This question is very open, as you can write an infinite amount differential equations But the first one wouldWebEn álgebra, una función cuadrática, un polinomio cuadrático, o un polinomio de grado 2, es una función polinómica con una o más variables en la que el término de grado más alto
Quadratic Function
The derivative of the given quadratic is (dy)/(dx) = 2x 4 By observation, this is equal to 0 when x=2 When x=2 the original equation becomes y = (2)^2 4(2)12 y = 16 Therefore the vertex of this parabola is at (2,16)Consider the length of chord passing through the vertex and inclined to the xaxis at an angle θ is L then the coordinate of point where chord cut the parabola is (x 1, y 1) = (Lcos θ, Lsin θ) This point is satisfying the equation of parabola y 2 = x ⇒ (Lsin θ) 2 = Lcos θ ⇒L 2 sin 2 θ = Lcos θ
